-8x^2-7x+4=0

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Solution for -8x^2-7x+4=0 equation:



-8x^2-7x+4=0
a = -8; b = -7; c = +4;
Δ = b2-4ac
Δ = -72-4·(-8)·4
Δ = 177
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{177}}{2*-8}=\frac{7-\sqrt{177}}{-16} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{177}}{2*-8}=\frac{7+\sqrt{177}}{-16} $

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